10=-16t^2+64t+8

Solution for 10=-16t^2+64t+8 equation:

10=-16t^2+64t+8

We move all terms to the left:

10-(-16t^2+64t+8)=0

We get rid of parentheses

16t^2-64t-8+10=0

We add all the numbers together, and all the variables

16t^2-64t+2=0

a = 16; b = -64; c = +2;
Δ = b2-4ac
Δ = -642-4·16·2
Δ = 3968
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3968}=\sqrt{64*62}=\sqrt{64}*\sqrt{62}=8\sqrt{62}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-8\sqrt{62}}{2*16}=\frac{64-8\sqrt{62}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+8\sqrt{62}}{2*16}=\frac{64+8\sqrt{62}}{32}
$